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4.2: Average ranking among WB/CW series in total viewers over the course of its 15 seasons. Its lowest finish was ninth in 2006-07, The CW's inaugural season. 4: The number of times its initial audience has fallen below 1 million viewers, all in the final season.The longer the series ran, some of the stories became repetitive, but the writers were able to take bigger risks with some arcs. As a result, the later seasons of the series might not be the greatest, but they certainly have some of the most creative elements of the show.
4.2: Average ranking among WB/CW series in total viewers over the course of its 15 seasons. Its lowest finish was ninth in 2006-07, The CW's inaugural season. 4: The number of times its initial audience has fallen below 1 million viewers, all in the final season.
The longer the series ran, some of the stories became repetitive, but the writers were able to take bigger risks with some arcs. As a result, the later seasons of the series might not be the greatest, but they certainly have some of the most creative elements of the show.
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Para encontrar uma razão de chances para numa dada probabilidade, primeiro expresse a certeza como um fração (usaremos 5/13). Subtraia o numerador (5) do denominador (13: 13 - 15 8). A resposta é O númerode resultados desfavoráveis”. As chances podem então ser expressadas assim5":8 –a proporção entre favorável e
desfavorável. resultados:
(Exemplo:)Se a probabilidade de um evento forde 0,80 (80%), A chance De que o acontecimento não ocorra é. 1-02,85 020 - ou 20%
20%. Então, neste exemplo: se a probabilidade do evento ocorrer 0,80 de então as chances sãode 0.90 / (1-0s78) -? 0,800/01,20 1> 4 (ou seja o4a
4) 1).